making vars in bash script accessible from shell
Price, Erik
eprice at ptc.com
Thu Nov 7 15:19:06 EST 2002
Hi,
I know there's some hardcore shell heads on this list, so I was hoping I could solicit some assistance here...
I've isolated the problem to an inability to make a variable declaration accessible outside of the script. It's almost as if there were a bash form of "use strict" going on that was keeping my variables within the scope of the script. If I try to echo $newPWD, I get nothing -- but I can see that $newPWD is getting set in the script. I've tried "export newPWD", which doesn't do anything either.
This is obviously some fundamental rule of variable scope in bash that I just don't know, so can someone set me right?
Bash v. 2.02 on Solaris.
Thanks,
Erik
#!/usr/local/bin/bash
#(yes, that's the location of bash on my system)
# How many characters of the $PWD should be kept
pwdmaxlen=30
# indicator that there has been directory truncation
trunc_symbol="..."
if [ ${#PWD} -gt $pwdmaxlen ]
then
pwdoffset=$(( ${#PWD} - $pwdmaxlen ))
newPWD="${trunc_symbol}${PWD:${pwdoffset}:${pwdmaxlen}}"
else
newPWD=${PWD}
fi
More information about the gnhlug-discuss
mailing list