making vars in bash script accessible from shell
Kevin D. Clark
kclark at CetaceanNetworks.com
Thu Nov 7 16:39:40 EST 2002
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characters -- thanks...]
> What exactly happens when you source a script (as opposed to executing it)?
The current shell runs the script instead of fork()-ing a new shell to
run it instead.
> What I'm doing is using the PROMPT_COMMAND variable to execute the shell [BAD WRAP]
>
> The problem is that this seems to only work at the moment Ire-source .bashrc [BAD WRAP]
>
> I suppose I need to escape the value of PROMPT_COMMAND so that it is not [BAD WRAP]
Is
PROMPT_COMMAND='pwd | perl -ne "chomp; print substr(\$_, 0, 30);"'
what you want?
Regards,
--kevin
--
Kevin D. Clark / Cetacean Networks / Portsmouth, N.H. (USA)
cetaceannetworks.com!kclark (GnuPG ID: B280F24E)
alumni.unh.edu!kdc
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