Advanced shell scripting question

[Kevin D. Clark]

jim.mcginness at att.net writes:

> When I
> tried it, it preserved the order of the output, thanks to
> the writer process being at a lower priority than the
> readers. 

This doesn't work either.  Try using the following program as input to
such a scheme:

     #include <stdio.h>
     
     int
     main(int argc, char *argv[])
     {
       int i;
     
       for (i=0; i<100000; i+=2) {
         printf("%d\n", i);
         fprintf(stderr, "%d\n", i+1);
       }
     }


Please see my previous posts for an explanation as to why.

Regards,

--kevin
-- 
Kevin D. Clark / Cetacean Networks / Portsmouth, N.H. (USA)
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