extract string

[klussier at comcast.net]

Actually, if you are looking for only lines that contain the string "univ", then you would want to grep for it:

grep univ abc.txt | cut -f3 -d, >> dev.txt.

Paul's example would give you the third field of each line, even if they don't have "univ" in them. Now, if you wanted to remove the quotes, then you would need something like:


grep univ abc.txt | cut -f3 -d, | sed s/\"//g >> dev.txt 

FYI,
Kenny

 -------------- Original message ----------------------
From: "Whelan, Paul" <Paul.Whelan at fmr.com>
> Like so: cat abc.txt | cut -d, -f3
> 
> Thanks.
> 
> -----Original Message-----
> From: Zhao Peng [mailto:greenmt at gmail.com] 
> Sent: Tuesday, January 10, 2006 11:51 AM
> To: gnhlug-discuss at mail.gnhlug.org
> Subject: extract string
> 
> Hi
> 
> Suppose that I have a file called abc.txt, which contains the following 
> 5 lines (columns are delimited by ",")
> 
> "name","age","school"
> "jerry" ,"21","univ of Vermont"
> "jesse","28","Dartmouth college"
> "jack","18","univ of Penn"
> "john","20","univ of south Florida"
> 
> My OS is RedHat Enterprise, how could I extract the string which 
> contains "univ" and create an output file called def.txt, which only has
> 
> 3 following lines:
> 
> univ of Vermont
> univ of Penn
> univ of south Florida
> 
> Please suggest the simplest command line approach.
> 
> Thank you.
> Zhao
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